I\'ve been trying to find the solution for this all day! You might label this as re-post but what I\'m really looking for is a solution without using boost lexical c
#include <sstream>
int main(int argc, char *argv[])
{
double f = 0.0;
std::stringstream ss;
std::string s = "3.1415";
ss << s;
ss >> f;
cout << f;
}
The good thing is, that this solution works for others also, like ints, etc.
If you want to repeatedly use the same buffer, you must do ss.clear
in between.
There is also a shorter solution available where you can initialize the value to a stringstream and flush it to a double at the same time:
#include <sstream>
int main(int argc, char *argv[]){
stringstream("3.1415")>>f ;
}
If you want to store (to a vector for example) all the doubles of a line
#include <iostream>
#include <vector>
#include <iterator>
int main()
{
std::istream_iterator<double> in(std::cin);
std::istream_iterator<double> eof;
std::vector<double> m(in,eof);
//print
std::copy(m.begin(),m.end(),std::ostream_iterator<double>(std::cout,"\n"));
}
Since C++11 you could use std::stod function:
string line;
double lineconverted;
try
{
lineconverted = std::stod(line);
}
catch(std::invalid_argument)
{
// can't convert
}
But solution with std::stringstream
also correct:
#include <sstream>
#include <string>
#include <iostream>
int main()
{
std::string str;
std::cin >> str;
std::istringstream iss(str);
double d = 0;
iss >> d;
std::cout << d << std::endl;
return 0;
}