Perfectly capturing a perfect forwarder (universal reference) in a lambda

Question

So I have a perfect forwarder, and I want to appropriately capture it in a lambda, such that R-values are copied in, and L-values are captured by reference. However simply

Answer 1

You may use the following:

[test = std::conditional_t<
             std::is_lvalue_reference<T>::value,
             std::reference_wrapper<std::remove_reference_t<T>>,
             T>{std::forward<T>(t)}]

Live Demo

but providing helper function seems more readable