Python: How to check if cell in CSV file is empty?

Question

I have a CSV file that I\'m reading in Python and I want the program to skip over the row if the first column is empty. How do I do this?

Right now I have:

Answer 1

I tried out what happens if you print and empty row and it returns [] (empty brackets)... so just check for that.

with open('testdata1.csv', 'rU') as csvfile:
    csvreader = csv.reader(csvfile)
    for row in csvreader:
        if row == []:
            continue
        #do stuff normally
   

Answer 2

You could use try and except.

for row in csvreader:
        try:
               #your code for cells which aren't empty
        except:
               #your code for empty cells

Answer 3

I would assume if you len() it then would be zero i.e.

if not len(row[0])

Answer 4

Small adaptation of Kit Fung's answer:

with open('testdata1.csv', 'r') as csv_file:
csv_reader = csv.reader(csv_file)
for row in csv_reader:
    if not row[0]:
         continue  # this will skip to the next for loop iteration
    # do your processing here

Answer 5

After hour of trying I was able to do it

while act_tab.cell(row=i, column=1).value is not None:
    ...

Answer 6

with open('testdata1.csv', 'r') as csvfile:
    csvreader = csv.reader(csvfile)
    for row in csvreader:
        print(row)
        if row[0] in (None, ""):
             print("12")

Reference: How do I detect missing fields in a CSV file in a Pythonic way?