Regular Expressions: Capture multiple groups using quantifier

Question

Consider the following code:

Answer 1

Count again (8 vs 9). pat2 and pat3 are missing the space in between the two parts.

Update: Additionally, I don't thing it's possible what you are trying to achieve by using match. See How can I match multiple occurrences with a regex in JavaScript similar to PHP's preg_match_all()? and use exec.

Answer 2

Why does neither pattern pat2 nor pat3 capture the first group rnbqkb-r?

Because you have white-space at the end of each 8-character sequence that your regexes pat2 and pat3 do not allow.

I would like to capture all groups without having to repeat them explicitly as in pattern pat1.

You can't.

It is not possible (in JavaScript) to capture two groups when your regex only contains one group.

Groups are defined thorugh parentheses. Your match result will contain as many groups as there are parentheses pairs in your regex (except modified parentheses like (?:...) which will not count towards match groups). Want two separate group matches in your match result? Define two separate groups in your regex.

If a group can match multiple times, the group's value will be whatever it matched last. All previous match occurrences for that group will be overridden by its last match.

Try

var pat1 = /^<12> ((?:[rnbqkp-]{8} ?)*)/i,
    match = str.match(pat1);

if (match) {
  match[1].split(/\s+/);  // ["rnbqkb-r", "Rnbq-b-r", ""]
}

Notes:

• Trim str beforehand if you don't want the last empty array value.
• In general, prefer regex literal notation (/expression/). Use new RegExp() only for expressions you generate from dynamic values.
• < and > are not special, you don't need to escape them.