The question was originally asked here as a comment but could not get a proper answer as the question was marked as a duplicate.
For a given pandas.Da
One way to overcome this is to make the 'A' column an index and use loc on the newly generated pandas.DataFrame. Eventually, the subsampled dataframe's index can be reset.
Here is how:
ret = df.set_index('A').loc[list_of_values].reset_index(inplace=False)
# ret is
# A B
# 0 3 3
# 1 4 5
# 2 6 2
Note that the drawback of this method is that the original indexing has been lost in the process.
More on pandas indexing: What is the point of indexing in pandas?
1] Generic approach for list_of_values.
In [936]: dff = df[df.A.isin(list_of_values)]
In [937]: dff.reindex(dff.A.map({x: i for i, x in enumerate(list_of_values)}).sort_values().index)
Out[937]:
A B
2 3 3
3 4 5
1 6 2
2] If list_of_values is sorted. You can use
In [926]: df[df.A.isin(list_of_values)].sort_values(by='A')
Out[926]:
A B
2 3 3
3 4 5
1 6 2
Use merge with helper DataFrame created by list and with column name of matched column:
df = pd.DataFrame({'A' : [5,6,3,4], 'B' : [1,2,3,5]})
list_of_values = [3,6,4]
df1 = pd.DataFrame({'A':list_of_values}).merge(df)
print (df1)
A B
0 3 3
1 6 2
2 4 5
For more general solution:
df = pd.DataFrame({'A' : [5,6,5,3,4,4,6,5], 'B':range(8)})
print (df)
A B
0 5 0
1 6 1
2 5 2
3 3 3
4 4 4
5 4 5
6 6 6
7 5 7
list_of_values = [6,4,3,7,7,4]
#create df from list
list_df = pd.DataFrame({'A':list_of_values})
print (list_df)
A
0 6
1 4
2 3
3 7
4 7
5 4
#column for original index values
df1 = df.reset_index()
#helper column for count duplicates values
df1['g'] = df1.groupby('A').cumcount()
list_df['g'] = list_df.groupby('A').cumcount()
#merge together, create index from column and remove g column
df = list_df.merge(df1).set_index('index').rename_axis(None).drop('g', axis=1)
print (df)
A B
1 6 1
4 4 4
3 3 3
5 4 5