I have some JSON data:
{\"humans\": [
{ \"firstName\" : \"Paul\", \"lastName\" : \"Taylor\", \"hairs\": 2 },
{ \"firstName\" : \"Sharon\", \"lastName
javascript for
loop is fastest:
var counter = 0;
for (var i = 0; i < data.humans.length; i++) {
if (data.humans[i].hairs === 2) {
counter++;
}
}
here's an example abstracting the grouping function and getting a list style result:
var data = {
"humans": [
{ "firstName" : "Paul", "lastName" : "Taylor", "hairs": 2 },
{ "firstName" : "Sharon", "lastName" : "Mohan", "hairs": 3 },
{ "firstName" : "Mohan", "lastName" : "Harris", "hairs": 3 },
{ "firstName" : "Deborah", "lastName" : "Goldman", "hairs": 4 },
{ "firstName" : "Mark", "lastName" : "Young", "hairs": 4 },
{ "firstName" : "Tom", "lastName" : "Perez", "hairs": 4 },
{ "firstName" : "Joseph", "lastName" : "Goldman", "hairs": 5 },
{ "firstName" : "Mary", "lastName" : "White", "hairs": 5 },
{ "firstName" : "Matthew", "lastName" : "Garcia", "hairs": 5 },
{ "firstName" : "Patricia", "lastName" : "Allen", "hairs": 5 },
{ "firstName" : "Larry", "lastName" : "Robinson", "hairs": 6 },
{ "firstName" : "Manb", "lastName" : "Lopez", "hairs": 6 },
{ "firstName" : "Jose", "lastName" : "Martinez", "hairs": 6 },
{ "firstName" : "Deborah", "lastName" : "Walker", "hairs": 6 },
{ "firstName" : "Joseph", "lastName" : "Lopez", "hairs": 6 },
{ "firstName" : "Tinman", "lastName" : "Moore", "hairs": 7 },
{ "firstName" : "Jose", "lastName" : "Jackson", "hairs": 7 },
{ "firstName" : "Karen", "lastName" : "Goldman", "hairs": 7 },
{ "firstName" : "Paul", "lastName" : "Taylor", "hairs": 7 },
{ "firstName" : "Amy", "lastName" : "Gonzalez", "hairs": 7 },
{ "firstName" : "Richard", "lastName" : "Martinez", "hairs": 7 }
]
};
function groupByHair(array, groupOf) {
var groups = {};
array.forEach(function(element) {
var groupName = groupOf(element);
if (groupName in groups)
groups[groupName].push(element);
else
groups[groupName] = [element];
});
return groups;
}
var byHairs = groupByHair(data.humans , function(h) {
return h.hairs;
});
for (var hairs in byHairs) {
var hairsN = byHairs[hairs].length;
console.log('in '+ hairs +'hairs-group you have: ' +hairsN+' people');
}
fiddle
You can use the filter function to filter an array of objects :
var data = {...}
data.humans.filter(function(o) { return o.hairs == 2 }).length
//Return the number of humans who have 2 hairs
Take a look fiddle
Can you try this ? It will group your data and you will get count for same.
var groupedData = _.groupBy(YourJsonName, function(d){return d.hairs});
My solution may be what you want
var data = {
"humans": [
{ "firstName" : "Paul", "lastName" : "Taylor", "hairs": 2 },
{ "firstName" : "Sharon", "lastName" : "Mohan", "hairs": 3 },
{ "firstName" : "Mohan", "lastName" : "Harris", "hairs": 3 },
{ "firstName" : "Deborah", "lastName" : "Goldman", "hairs": 4 },
{ "firstName" : "Mark", "lastName" : "Young", "hairs": 4 },
{ "firstName" : "Tom", "lastName" : "Perez", "hairs": 4 },
{ "firstName" : "Joseph", "lastName" : "Goldman", "hairs": 5 },
{ "firstName" : "Mary", "lastName" : "White", "hairs": 5 },
{ "firstName" : "Matthew", "lastName" : "Garcia", "hairs": 5 },
{ "firstName" : "Patricia", "lastName" : "Allen", "hairs": 5 },
{ "firstName" : "Larry", "lastName" : "Robinson", "hairs": 6 },
{ "firstName" : "Manb", "lastName" : "Lopez", "hairs": 6 },
{ "firstName" : "Jose", "lastName" : "Martinez", "hairs": 6 },
{ "firstName" : "Deborah", "lastName" : "Walker", "hairs": 6 },
{ "firstName" : "Joseph", "lastName" : "Lopez", "hairs": 6 },
{ "firstName" : "Tinman", "lastName" : "Moore", "hairs": 7 },
{ "firstName" : "Jose", "lastName" : "Jackson", "hairs": 7 },
{ "firstName" : "Karen", "lastName" : "Goldman", "hairs": 7 },
{ "firstName" : "Paul", "lastName" : "Taylor", "hairs": 7 },
{ "firstName" : "Amy", "lastName" : "Gonzalez", "hairs": 7 },
{ "firstName" : "Richard", "lastName" : "Martinez", "hairs": 7 }
]
};
var counterList = [];
$.each(data.humans,function(i,item){
counterList.push(item.hairs);
});
$.extend({
distinct : function(anArray) {
var result = [];
$.each(anArray, function(i,v){
if ($.inArray(v, result) == -1) result.push(v);
});
return result;
}
});
var uniqueCounterList= $.distinct(counterList);
var html = "";
$.each(uniqueCounterList,function(j,itemUnique){
html += "<div>Hair "+itemUnique+": "+(data.humans.filter(function(o) { return o.hairs == itemUnique }).length)+"</div>";
});
$("#count").html(html);
Or http://jsfiddle.net/8g5ggfeh/