Updating multiple rows with node-mysql, NodeJS and Q

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-上瘾入骨i
-上瘾入骨i 2020-12-16 22:44

I am using node-mysql, node-js, and Q promises.

I have successfully updated, deleted, and inserted single rows using the above. As well as inserted multiple rows in

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  • 2020-12-16 23:02

    You can do it this way:

    var values = [
      { users: "tom", id: 101 },
      { users: "george", id: 102 }
    ];
    var queries = '';
    
    values.forEach(function (item) {
      queries += mysql.format("UPDATE tabletest SET users = ? WHERE id = ?; ", item);
    });
    
    connection.query(queries, defered.makeNodeResolver());
    

    To use multiple statements feature you have to enable it for your connection:

    var connection = mysql.createConnection({
      ...
      multipleStatements: true,
    });
    
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  • 2020-12-16 23:06

    Don't know if this problem it's still relevant but I will give my 2 cents:

    The solution that I found is to use Promise.all

    Basically you need to build an array of promises, where every promise is an update statement:

    const getUpdatePromise = (row) => {
      return new Promise( (resolve, reject) => {
        mysqlConnection.query('UPDATE tableName SET foo = ? WHERE bar = ?', [row[0], row[1], (error, results, fields) => {
          if (error) reject(error)
          resolve(results)
        });
      })
    }

    You add this new Promise into an array and pass the final array with all the update statements to the Promise.all function.

    It worked for me. Hope it works for someone else.

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  • 2020-12-16 23:15

    I don't think you can (at least easily/efficiently) update multiple rows in the way you are trying. You would basically have to loop over your values and execute an UPDATE for each object.

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  • 2020-12-16 23:16

    this piece of code was taken from vcl.js for node.js, it is written in typescript and provides a multiple update,delete,inseer statment's in a single transaction.

    export class SQLStatment {
        sql: string;
        params: Object
    }
    
    var dbError: string;
    var execCount: number = 0;
    function DBexecuteBatchMYSQLSingle(connection: any, SQLStatmentArray: Array<SQLStatment>, index: number, callback: () => void) {
        execCount++;
        connection.query(SQLStatmentArray[index].sql, SQLStatmentArray[index].params, function (err, rows, fields) {
            if (err) dbError = err;
            if (index + 1 == SQLStatmentArray.length) callback();
            else {
                if (!dbError) {
                    DBexecuteBatchMYSQLSingle(connection, SQLStatmentArray, index + 1, function () {
                        if (index == 0) callback();
                    });
                }
            }
        });
    }
    
    function DBBatchUpdateMYSQL(SQLStatmentArray: Array<SQLStatment>, callback?: (err) => void) {
        var mysql = require('mysql');
        var connection = mysql.createConnection({
            host: "host",user: "user",database: "db",
            port: 1022, password: "pass"});
        dbError = null;
        execCount = 0;
        connection.beginTransaction(function (err) {
            if (err && callback) callback("Database error:" + err);
            else {
                DBexecuteBatchMYSQLSingle(connection, SQLStatmentArray, 0, () => {
                    if (dbError) {
                        connection.rollback(function () {
                            if (callback) callback("Database error:" + dbError);
                        });
                    } else {
                        connection.commit(function (err) {
                            if (callback) callback(null);
                        })
                    }
                });
            }
        });
    }
    
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  • 2020-12-16 23:18

    You should probably do following way

    UPDATE DB.table
    SET table.row = newValue WHERE table.someColumn in ('columnVal1', 'columnVal2');
    

    ex.

    UPDATE DB.Students
    SET result = "pass" WHERE rollNo in (21, 34, 50);
    
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