two SQL COUNT() queries?

Question

I want to count both the total # of records in a table, and the total # of records that match certain conditions. I can do these with two separate queries:

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Answer 1

if you are just counting rows you could just use nested queries.

select 
    (SELECT COUNT(*) AS TotalCount FROM MyTable) as a,
    (SELECT COUNT(*) AS QualifiedCount FROM MyTable WHERE {conditions}) as b

Answer 2

MySQL doesn't count NULLs, so this should work too:

SELECT count(*) AS TotalCount, 
  count( if( field = value, field, null)) AS QualifiedCount 
  FROM MyTable {possible JOIN(s)} WHERE {some conditions}

That works well if the QuailifiedCount field comes from a LEFT JOIN, and you only care if it exists. To get the number of users, and the number of users that have filled in their address:

SELECT count( user.id) as NumUsers, count( address.id) as NumAddresses
  FROM Users
  LEFT JOIN Address on User.address_id = Address.id;

Answer 3

In Sql Server or MySQL, you can do that with a CASE statement:

select 
    count(*) as TotalCount,
    sum(case when {conditions} then 1 else 0 end) as QualifiedCount
from MyTable

Edit: This also works if you use a JOIN in the condition:

select 
    count(*) as TotalCount,
    sum(case when {conditions} then 1 else 0 end) as QualifiedCount
from MyTable t
left join MyChair c on c.TableId = t.Id
group by t.id, t.[othercolums]

The GROUP BY is there to ensure you only find one row from the main table.

Answer 4

One way is to join the table against itself:

select
   count(*) as TotalCount,
   count(s.id) as QualifiedCount
from
   MyTable a
left join
   MyTable s on s.id = a.id and {some conditions}

Another way is to use subqueries:

select
   (select count(*) from Mytable) as TotalCount,
   (select count(*) from Mytable where {some conditions}) as QualifiedCount

Or you can put the conditions in a case:

select
   count(*) as TotalCount,
   sum(case when {some conditions} then 1 else 0 end) as QualifiedCount
from
   MyTable

Related:

SQL Combining several SELECT results

Answer 5

In Oracle SQL Developer I had to add a * FROM in my select, or else i was getting a syntax error:

select * FROM 
    (select COUNT(*) as foo FROM TABLE1),
    (select COUNT(*) as boo FROM TABLE2);