Sub-classing float type in Python, fails to catch exception in __init__()

Question

On Python 2.5 I need to use float numbers with a modified __str__() method. Also I need to know when the constructor fails.

Why I can\'t catch exception

Answer 1

float is immutable, therefore its __init__, the initializer, is basically a no-op -- nothing substantial can happen there, because the self object cannot be altered (if it's actually an instance of float rather than of a subclass -- but of course float's own __init__ must operate on that assumption;-).

Therefore, all the action happens in __new__, the constructor proper, just like for other immutable types like int, str, tuple, and so on. It's a common mistake to believe that __init__ is a constructor: it's not, it takes an already-constructed object as its first argument, self, and "initializes" it (if feasible, i.e., if that self is mutable!-) -- the construction itself happens in __new__.

So, your float subclass should start:

class My_Number(float):
  def __new__(cls, float_string):
    try: return float.__new__(cls, float_string)
    except (TypeError, ValueError): raise My_Error(float_string)

and you can remove the __init__, which is not needed. Now:

>>> n = My_Number('foo')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 4, in __new__
NameError: global name 'My_Error' is not defined

(of course, it would work even better if you did have a My_Error exception class defined;-).

Answer 2

try __new__ instead:

class F(float):
    def __new__(cls, *arg, **kw):
        try:
            return float.__new__(cls, *arg, **kw)
        except ValueError:
            raise Exception("foo")

print F("3.5")            
print F("asdf")

Also "self" is a float already so no need to say float(self), just "self" will do:

def __str__(self):
    return "%.2f" % self