This seems like it should be a fairly easy problem to solve but I am having some trouble locating an answer.
I have a vector which contains long decimals and I want
Not the most elegant way, but it'll work.
string_it<-sprintf("%06.9f", old_numbers)
pos_list<-gregexpr(pattern="\\.", string_it)
pos<-unlist(lapply(pos_list, '[[', 1)) # This returns a vector with the first
#elements
#you're probably going to have to play around with the pos- numbers here
new_number<-as.numeric(substring(string_it, pos-1,pos+4))
I used the technics above for a long time. One day I had some issues when I was copying the results to a text file and I solved my problem in this way:
trunc_number_n_decimals <- function(numberToTrunc, nDecimals){
numberToTrunc <- numberToTrunc + (10^-(nDecimals+5))
splitNumber <- strsplit(x=format(numberToTrunc, digits=20, format=f), split="\\.")[[1]]
decimalPartTrunc <- substr(x=splitNumber[2], start=1, stop=nDecimals)
truncatedNumber <- as.numeric(paste0(splitNumber[1], ".", decimalPartTrunc))
return(truncatedNumber)
}
print(trunc_number_n_decimals(9.1762034354551236, 6), digits=14)
[1] 9.176203
print(trunc_number_n_decimals(9.1762034354551236, 7), digits=14)
[1] 9.1762034
print(trunc_number_n_decimals(9.1762034354551236, 8), digits=14)
[1] 9.17620343
print(trunc_number_n_decimals(9.1762034354551236, 9), digits=14)
[1] 9.176203435
This solution is very handy in cases when its necessary to write to a file the number with many decimals, such as 16. Just remember to convert the number to string before writing to the file, using format()
numberToWrite <- format(trunc_number_n_decimals(9.1762034354551236, 9), digits=20)
trunc(x*10^4)/10^4
yields 0.1234
like expected.
More generally,
trunc <- function(x, ..., prec = 0) base::trunc(x * 10^prec, ...) / 10^prec;
print(trunc(0.123456789, prec = 4) # 0.1234
print(trunc(14035, prec = -2), # 14000