I\'m trying to install tomcat-7.0.27 on windows 7. I then clicked bin/startup.bat, a window shows up and I see \"INFO: Server startup in 761 ms\" at the last line. I then tr
The problem is that the user that is running Tomcat lacks file permissions (read/write) in the install folder.
Solution
Right-click on the Tomcat folder (apache-tomcat-7.0.29), select "Properties", go to the "Security tab", try to give it full control to any users profile in you pc, just for be sure.
Then, click again to C:\Program Files (x86)\Apache Software Foundation\apache-tomcat-7.0.29\bin\startup.bat and wait for self creation of the folders by the application "startup.bat".
Other option is manually (I created the following directories by hand):
if this was working for you previously, sometimes the work directory is simply in a bad state and you can fix it by deleting it and allowing tomcat to create a new one from scratch.
What worked for me: Go to your tomcat installation bin directory, for me: C:\Program Files\Apache Software Foundation\apache-tomcat-7.0.37\bin. Right-click "startup.bat" and select "Run as Administrator"
Windows 7 makes it easy to run into such trouble when you are not careful enough installing things. You will have to make sure that the SYSTEM user has full access to the Tomcat folder, so that when Tomcat runs, it can freely create folders and files within its own directory.
I got the same problem but it can easy be solved with administrative rights,just opened command prompt with administrative rights and it worked!!! Hope will help others..
I got this problem with windows 8 and running the "startup.bat" was not working.
I fixed it by going to my JazzTeamServer Folder (i was installing Jazz CLM), right click in the folder, properties, security, edit, and mark as full control for the Group that you are using.
After that, the Tomcat server is able to create all the folders that it requires.
Hope this helps, this is my first answer in SO. ;)