Match number at the end of the string

Question

Given the following string how can I match the entire number at the end of it?

$string = \"Conacu P PPL Europe/Bucharest 680979\";

I have t

Answer 1

You could use a regex with preg_match, like this :

$string = "Conacu P PPL Europe/Bucharest 680979";

$matches = array();
if (preg_match('#(\d+)$#', $string, $matches)) {
    var_dump($matches[1]);
}

And you'll get :

string '680979' (length=6)

And here is some information:

• The # at the beginning and the end of the regex are the delimiters -- they don't mean anything : they just indicate the beginning and end of the regex ; and you could use whatever character you want (people often use / )
• The '$' at the end of the pattern means "end of the string"
• the () means you want to capture what is between them
  • with preg_match, the array given as third parameter will contain those captured data
  • the first item in that array will be the whole matched string
  • and the next ones will contain each data matched in a set of ()
• the \d means "a number"
• and the + means one or more time

So :

• match one or more number
• at the end of the string

For more information, you can take a look at PCRE Patterns and Pattern Syntax.

Answer 2

The following regex should do the trick:

/(\d+)$/

Answer 3

EDIT: This answer checks if the very last character in a string is a digit or not. As the question https://stackoverflow.com/q/12258656/1331430 was closed as an exact duplicate of this one, I'll post my answer for it here. For what this question's OP is requesting though, use the accepted answer.

---

Here's my non-regex solution for checking if the last character in a string is a digit:

if (ctype_digit(substr($string, -1))) {
    //last character in string is a digit.
}

DEMO

substr passing start=-1 will return the last character of the string, which then is checked against ctype_digit which will return true if the character is a digit, or false otherwise.

References:

1. substr
2. ctype_digit