Split by comma and how to exclude comma from quotes in split … Python

Question

python 2.7 code

cStr = \'\"aaaa\",\"bbbb\",\"ccc,ffffd\"\' 

newStr = cStr.split(\',\')

print newStr 

# result : [\'\"aaaa\"\',\'\"bbbb\"\',\'\"ccc\',\'ffffd\         


        

Answer 1

You can first split the string by " then filter out '' or ',', finally format it, it may be the simplest way:

['"%s"' % s for s in cStr.split('"') if s and s != ',']

Answer 2

This is not a standard module, you have to install it via pip, but as an option try tssplit:

In [3]: from tssplit import tssplit
In [4]: tssplit('"aaaa","bbbb","ccc,ffffd"', quote='"', delimiter=',')                                                            
Out[4]: ['aaaa', 'bbbb', 'ccc,ffffd']

Answer 3

pyparsing has a builtin expression, commaSeparatedList:

cStr = '"aaaa","bbbb","ccc,ffffd"' 
import pyparsing as pp
print(pp.commaSeparatedList.parseString(cStr).asList())

prints:

['"aaaa"', '"bbbb"', '"ccc,ffffd"']

You can also add a parse-time action to strip those double-quotes (since you probably just want the content, not the quotation marks too):

csv_line = pp.commaSeparatedList.copy().addParseAction(pp.tokenMap(lambda s: s.strip('"')))
print(csv_line.parseString(cStr).asList())

gives:

['aaaa', 'bbbb', 'ccc,ffffd']

Answer 4

By using regex try this:

COMMA_MATCHER = re.compile(r",(?=(?:[^\"']*[\"'][^\"']*[\"'])*[^\"']*$)")
split_result = COMMA_MATCHER.split(string)

Answer 5

The solution using re.split() function:

import re

cStr = '"aaaa","bbbb","ccc,ffffd"'
newStr = re.split(r',(?=")', cStr)

print newStr

The output:

['"aaaa"', '"bbbb"', '"ccc,ffffd"']

---

,(?=") - lookahead positive assertion, ensures that delimiter , is followed by double quote "

Answer 6

Try to use CSV.

import csv
cStr = '"aaaa","bbbb","ccc,ffffd"'
newStr = [ '"{}"'.format(x) for x in list(csv.reader([cStr], delimiter=',', quotechar='"'))[0] ]

print newStr

Check Python parse CSV ignoring comma with double-quotes