PHP try-catch not working

Question

try     
{
    $matrix = Query::take(\"SELECT moo\"); //this makes 0 sense

    while($row = mysqli_fetch_array($matrix, MYSQL_BOTH)) //and thus this line should be          


        

Answer 1

Exception is only subclass of Throwable. To catch error you can try to do one of the following:

try {

    catch (\Exception $e) {
       //do something when exception is thrown
}
catch (\Error $e) {
  //do something when error is thrown
}

OR more inclusive solution

try {

catch (\Exception $e) {
   //do something when exception is thrown
}
catch (\Throwable $e) {
  //do something when Throwable is thrown
}

BTW : Java has similar behaviour.

Answer 2

PHP is generating a warning, not an exception. Warnings can't be caught. They are more like compiler warnings in C#.

Answer 3

You can't handle Warnings/Errors with try-catch blocks, because they aren't exceptions. If you want to handle warnings/errors, you have to register your own error handler with set_error_handler.

But it's better to fix this issue, because you could prevent it.

Answer 4

In PHP a warning is not an exception. Generally the best practice would be to use defensive coding to make sure the result is what you expect it to be.

Answer 5

Welp, unfortunately this is the issue about PHP. Try/catch statements will catch Exceptions, but what you're receiving is an old-school PHP error.

You'll have to catch an error like this with: http://php.net/manual/en/function.set-error-handler.php

Either that or check to see if $matrix is a mysqli_result object prior to performing mysqli_fetch_array.