How do I convert boolean values to integers?

Question

I have a boolean value to check if it is true, then set a local variable. How do I refactor this so it is more Ruby-ish?

if firm.inflection_point
  inflectio         


        

Answer 1

Here's another method:

5 - bool.to_s.length

This takes advantage of the fact that 'true' has four characters, while 'false' has 5.

Answer 2

Another alternative is use of short-circuit operators:

inflection_point && 1 || 0


irb(main):001:0> true && 1 || 0
=> 1
irb(main):002:0> false && 1 || 0
=> 0

Answer 3

inflection_point = (firm.inflection_point ? 1 : 0)

Answer 4

In Ruby, if is an expression. There's no need to assign to a variable inside the then and else branches, just return the value you want and assign the variable to the result of the if expression:

inflection_point = if firm.inflection_point
  1
else
  0
end

In simple cases like this, it's more readable to write the entire expression on a single line:

inflection_point = if firm.inflection_point then 1 else 0 end

You can also use the conditional operator, which I personally find to be much less readable:

inflection_point = firm.inflection_point ? 1 : 0

Answer 5

What you need is a conditional operation that is known as Ternary Operator It's used in almost every language and it uses the symbols ? and :

inflection_point = firm.inflection_point ? 1 : 0

basically means, if the first condition evaluates to true (firm.inflection_point), return the value after "?" (1) otherwise, return the value after ":" (0)

Answer 6

It is not pure ruby solution but, You can use ActiveRecord::Type::Integer.new.cast(true)