Can I use TypeScript overloads when using fat arrow syntax for class methods?

Question

I\'ve converted some classes from the conventional form:

class TestOverloads {
    private status = \"blah\";
    public doStuff(selector: JQuery);
    publi         


        

Answer 1

You can write an inline type literal for the call signatures the function supports:

class TestOverloads2 {
    private status = "blah";
    public doStuff: {
        (selector: JQuery): void;
        (selector: string): void;
    } = (selector: any) => {
        alert(this.status);
    }
}

That's sort of hideous, so you might want to extract it into an interface instead:

interface SelectByJQueryOrString {
    (selector: JQuery): void;
    (selector: string): void;
}

class TestOverloads3 {
    private status = "blah";
    public doStuff: SelectByJQueryOrString = (selector: any) => {
        alert(this.status);
    }
}

Answer 2

It is a bit of a technicality, but you are no longer creating a function, you are creating a property (that happens to be a function).

You could solve your problem using naming rather than overloading though.

class TestOverloads2 {
    private status = "blah";
    public doStuffWithSelector = (selector: string) => {
        alert(this.status);
    }
    public doStuffWithJqueryObject = (jqo: JQuery) => {
        alert(this.status);
    }
}

If there is significant duplication, you can put that in a common function that both named functions call, for example: this.sharedStuff().