How to hide ticks label in python but keep the ticks in place?

Question

I want to hide my ticks label on a plot I created, but keep this tick itself (the little marks on the axis). When I try to use what I\'ve found here, for example, the entire

Answer 1

I didn't find divenex's answer to work for me. This answer creates ticks without triggering any automatic labeling, hence no requirement to use "labelbottom= False":

if the bottom and left ticks already exist:

import matplotlib.pyplot as plt

fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])

ax.tick_params(right= True,top= True)

if no ticks already exist:

import matplotlib.pyplot as plt

fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])

ax.tick_params(right= True,top= True,left= True, bottom= True)

Answer 2

Here is a slightly simpler answer, using ax.tick_params

import matplotlib.pylab as plt

fig, ax = plt.subplots()
plt.plot([1,2,3],[4,5,6])

ax.tick_params(labelbottom=False)    

plt.show()

Here is the resulting output in Matplotlib 3

As commented by @chris, one can similarly hide the labels on any of the other axes using labeltop, labelleft, labelright, in the above example, instead of labelbottom.

Answer 3

Set the tick labels not to be an empty array, but to be a list of empty strings. In the example below, I've replaced the xtick labels with empty strings, leaving the y axis untouched. From here you can selectively keep certain labels if you wished.

import pylab as plt

fig, ax = plt.subplots()
ax.plot([1,2,3],[4,5,6])

labels = [item.get_text() for item in ax.get_xticklabels()]

empty_string_labels = ['']*len(labels)
ax.set_xticklabels(empty_string_labels)

plt.show()

This code is adapted from a previous answer.