mysql-function to count days between 2 dates excluding weekends

Question

I\'ve searched through many examples , good ones I got :

1. Count days between two dates, excluding weekends (MySQL only)

2. How to count date dif

Answer 1

UPDATED: If you just need a number of weekdays between two dates you can get it like this

CREATE FUNCTION TOTAL_WEEKDAYS(date1 DATE, date2 DATE)
RETURNS INT
RETURN ABS(DATEDIFF(date2, date1)) + 1
     - ABS(DATEDIFF(ADDDATE(date2, INTERVAL 1 - DAYOFWEEK(date2) DAY),
                    ADDDATE(date1, INTERVAL 1 - DAYOFWEEK(date1) DAY))) / 7 * 2
     - (DAYOFWEEK(IF(date1 < date2, date1, date2)) = 1)
     - (DAYOFWEEK(IF(date1 > date2, date1, date2)) = 7);

Note: The function will still work if you switch start date1 and end date2 dates.

Sample usage:

SELECT TOTAL_WEEKDAYS('2013-08-03', '2013-08-21') weekdays1,
       TOTAL_WEEKDAYS('2013-08-21', '2013-08-03') weekdays2;

Output:

| WEEKDAYS1 | WEEKDAYS2 |
-------------------------
|        13 |        13 |

Here is DBFiddle demo

Answer 2

Had a similar issue, I used PHP to remove the weekends, need to know start day and number of days:

EG SQL:

  SELECT DAYOFWEEK(`date1`) AS `startday`, TIMESTAMPDIFF(DAY, `date1`, `date2`) AS `interval` FROM `table`

Then run the result through a PHP function:

    function noweekends($startday, $interval) {
        //Remove weekends from an interval
        $wecount = 0; $tmp = $interval;
        while($interval/7 > 1) { $interval-=7; $wecount++; }
        if($interval+$startday > 5) $wecount++;
        $interval = $tmp-($wecount*2);
        return $interval;
    }

Answer 3

This query will work fine, all the queries above are not working well. Try this :

SELECT ((DATEDIFF(date2, date1)) -
        ((WEEK(date2) - WEEK(date1)) * 2) -
        (case when weekday(date2) = 6 then 1 else 0 end) -
        (case when weekday(date1) = 5 then 1 else 0 end)) as DifD

Test it like this :

SELECT ((DATEDIFF('2014-10-25', '2014-10-15')) -
            ((WEEK('2014-10-25') - WEEK('2014-10-15')) * 2) -
            (case when weekday('2014-10-25') = 6 then 1 else 0 end) -
            (case when weekday('2014-10-15') = 5 then 1 else 0 end)) as DifD

The result :

DifD    
8

Answer 4

I use this. Means there are no functions so can be used in views:

select 
datediff(@dateto, @datefrom) + 
datediff(@datefrom, 
    date_add(@datefrom, INTERVAL 
     floor(datediff(@dateto, @datefrom) / 7) day)) * 2
- case
    when weekday(@dateto) = 6 then 2
    when weekday(@dateto) = 5 then 1
    when weekday(@dateto) < weekday(@datefrom) then 2
    else 0 
end;