Exception in thread “main” java.lang.StringIndexOutOfBoundsException: String index out of range: 11

Question

EVerytime I write any code similar to this one, I get this type of error. It\'s building a file but not letting it run, it just throws exception. I\'m not familiar with exce

Answer 1

try this:

public static void main(String args[]) {
String name = "Umer Hassan";
String name1 = "Hassan Umer";
char[] name2 = new char[name.length()];

for (int j = 0; j < name.length(); j++ {
    for (int i = 0; i < name.length(); i++) {
        if (name.length() == name1.length()) {
            if (name.charAt(i) == name1.charAt(j)) {
                name2[i] = name1.charAt(j);
            }
        }
    }
}

}

Answer 2

Your loop control variables (i / j) are going up to name.length() - which is an out of bounds index (since the max index of a string/list is len - 1 - remember the first index is 0).

Try using i < name.length() and j < name.length() as the loop conditions instead.

Answer 3

You should write the for cycle as

for (int i = 0; i < name.length(); i++)

The indexes in the strings are zero-based, as in the arrays, so they have a range from 0 to length - 1. You go to length, which is outside of bounds.

Answer 4

for (int i=0; i<=name.length();i++){

String indexes are starting from 0 .

Example :

String str = "abc";
int len = str.length(); //will return 3

str.charAt(3); will throws StringIndexOutOfBoundsException charAt starting position is 0 . So the limit is length-1 .

You have to change your for loop to for (int i=0; i<name.length();i++){