I have the follow class and the list that holds it:
public class Transport
{
public string TransportType { get; set; }
public string Mode { get; set;
You need a stream and a XmlSerializer object, here's an example:
FileStream fs = new FileStream(@"C:\MyPath", FileMode.OpenOrCreate);
xmlSerializer = new XmlSerializer(typeof(MyClass));
xmlSerializer.Serialize(fs, myClassInstance);
fs.Flush();
fs.Close();
fs.Dispose();
Don't forget to handle errors your own way. And I'm also assuming you want to serialize all your class' properties.
If both of your classes were tagged with the [Serializable]
attribute, then saving things to a file should be as simple as:
var serializer = new XmlSerializer(typeof(Transport));
using(var writer = new StreamWriter("C:\\Path\\To\\File.xml"))
{
serializer.Serialize(writer, instance);
}
Update
Sorry, didn't realize you were asking about how to customize the output. That is what the [XmlAttribute]
and [XmlElement]
attributes are for:
public class Transport
{
// Store TransportType as an attrribute called Type in the XML
[XmlAttribute("Type")]
public string TransportType { get; set; }
// Rest of Implementation
}