Say I have a table which I query like so:
select date, value from mytable order by date
and this gives me results:
date
This is a simplified version of @Bob Jarvis' answer, the main difference being the use of just one subquery instead of four,
with f as (select row_number() over(order by d) rn, d, v from t3)
select
a.d, a.v,
case when a.v in (prev.v, next.v) then '*' end match
from
f a
left join
f prev
on a.rn = prev.rn + 1
left join
f next
on a.rn = next.rn - 1
order by a.d
;
As @Janek Bogucki has pointed out LEAD and LAG are probably the easiest way to accomplish this - but just for fun let's try to do it by using only basic join operations:
SELECT mydate, VALUE FROM
(SELECT a.mydate, a.value,
CASE WHEN a.value = b.value THEN '*' ELSE NULL END AS flag1,
CASE WHEN a.value = c.value THEN '*' ELSE NULL END AS flag2
FROM
(SELECT ROWNUM AS outer_rownum, mydate, VALUE
FROM mytable
ORDER BY mydate) a
LEFT OUTER JOIN
(select ROWNUM-1 AS inner_rownum, mydate, VALUE
from mytable
order by myDATE) b
ON b.inner_rownum = a.outer_rownum
LEFT OUTER JOIN
(select ROWNUM+1 AS inner_rownum, mydate, VALUE
from mytable
order by myDATE) c
ON c.inner_rownum = a.outer_rownum
ORDER BY a.mydate)
WHERE flag1 = '*' OR
flag2 = '*';
Share and enjoy.
Use the lead and lag analytic functions.
create table t3 (d number, v number);
insert into t3(d, v) values(1, 1);
insert into t3(d, v) values(2, 2);
insert into t3(d, v) values(3, 2);
insert into t3(d, v) values(4, 3);
insert into t3(d, v) values(5, 2);
insert into t3(d, v) values(6, 3);
insert into t3(d, v) values(7, 4);
select d, v, case when v in (prev, next) then '*' end match, prev, next from (
select
d,
v,
lag(v, 1) over (order by d) prev,
lead(v, 1) over (order by d) next
from
t3
)
order by
d
;
Matching neighbours are marked with * in the match column,