How to sort ip address in ascending order

Question

Is there any method to sort this? Or do I just need to split it and use a loop to compare? Input

123.4.245.23
104.244.253.29
1.198.3.93
32.183.93.40
104.30.2         


        

Answer 1

public class IpSort {  
    public static void main(String[] args) {  
        // TODO Auto-generated method stub  
        String[] arr = {"192.168.1.1",  
            "191.122.123.112",  
            "192.161.1.1",  
            "191.122.123.1",  
            "123.24.5.78",  
            "121.24.5.78",  
            "123.24.4.78",  
            "123.2.5.78",  
            "192.1.1.1",  
            "125.45.67.89",  
            "1.1.1.1",  
            "3.4.5.6",  
            "2.2.2.2",  
            "6.6.6.7",  
            "155.155.23.0"};  
        String tmp;  
        for(int i=0;i<arr.length;i++)  
        {  
                  for(int j=1;j<arr.length-i;j++)  
                  {  
                      String[] instr1 = arr[j-1].split("\\.");  
                      String[] instr2 = arr[j].split("\\.");  
                           if(Integer.parseInt(instr1[0]) > Integer.parseInt(instr2[0]))  
                           {  
                               tmp=arr[j-1];  
                               arr[j-1]=arr[j];  
                               arr[j]=tmp;  
                           }else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) > Integer.parseInt(instr2[1]) )  
                           {  
                                tmp=arr[j-1];  
                                arr[j-1]=arr[j];  
                                arr[j]=tmp;  
                           } else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) == Integer.parseInt(instr2[1])  
                         && Integer.parseInt(instr1[2]) > Integer.parseInt(instr2[2]) )  
                           {  
                                tmp=arr[j-1];  
                                arr[j-1]=arr[j];  
                                arr[j]=tmp;  
                           } else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) == Integer.parseInt(instr2[1])  
                         && Integer.parseInt(instr1[2]) == Integer.parseInt(instr2[2])  
                         && Integer.parseInt(instr1[3]) > Integer.parseInt(instr2[3]) )  
                           {  
                               tmp=arr[j-1];  
                               arr[j-1]=arr[j];  
                               arr[j]=tmp;  
                           }  
                  }  

        }  
        System.out.println("final sorted list of ips :\n");  
        for(int k=0;k<arr.length;k++){  
            System.out.println(arr[k]);  
        }  
    }  
}  

Answer 2

I would suggest to implement your own Comparator. See this post: Sorting IP addresses in Java

Copy paste only for you:

/**
 * LGPL
 */
public class InetAddressComparator implements Comparator {
    @Override
    public int compare(InetAddress adr1, InetAddress adr2) {
        byte[] ba1 = adr1.getAddress();
        byte[] ba2 = adr2.getAddress();

        // general ordering: ipv4 before ipv6
        if(ba1.length < ba2.length) return -1;
        if(ba1.length > ba2.length) return 1;

        // we have 2 ips of the same type, so we have to compare each byte
        for(int i = 0; i < ba1.length; i++) {
            int b1 = unsignedByteToInt(ba1[i]);
            int b2 = unsignedByteToInt(ba2[i]);
            if(b1 == b2)
                continue;
            if(b1 < b2)
                return -1;
            else
                return 1;
        }
        return 0;
    }

    private int unsignedByteToInt(byte b) {
        return (int) b & 0xFF;
    }
}

Answer 3

Try this one

@Override
public int compare(Object adr1, Object adr2) {
    try
    {
        if(adr1 == null || adr1.toString().isEmpty()) return -1;
        if(adr2 == null || adr2.toString().isEmpty()) return 1;
        String[] ba1 = adr1.toString().split( "\\." );
        String[] ba2 = adr2.toString().split( "\\." );

        for ( int i = 0; i < ba1.length; i++ )
        {
            int b1 = Integer.parseInt( ba1[ i ] );
            int b2 = Integer.parseInt( ba2[ i ] );

            if (b1 == b2)
                continue;
            if (b1 < b2)
                return -1;
            else
                return 1;
        }
        return 0;
    }
    catch ( Exception ex )
    {
        return 0;
    }

}