Java Program to test if a character is uppercase/lowercase/number/vowel [closed]

Answer 1

If it weren't a homework, you could use existing methods such as Character.isDigit(char), Character.isUpperCase(char) and Character.isLowerCase(char) which are a bit "smarter", because they don't operate only in ASCII, but also in various charsets.

static final char[] VOWELS = { 'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U' };

static boolean isVowel(char ch) {
    for (char vowel : VOWELS) {
        if (vowel == ch) {
            return true;
        }
    }
    return false;
}

static boolean isDigit(char ch) {
    return ch >= '0' && ch <= '9';
}

static boolean isLowerCase(char ch) {
    return ch >= 'a' && ch <= 'z';
}

static boolean isUpperCase(char ch) {
    return ch >= 'A' && ch <= 'Z';
}

Answer 2

Some comments on your code

• why would you want to have 2 for loops like for(i='A';i<='Z';i++), if you can check this with a simple if statement ... you loop over a whole range while you can simply check whether it is contained in that range
• even when you found your answer (for example when input is A you will have your result the first time you enter the first loop) you still loop over all the rest
• your System.out.println("Lowercase"); statement (and the uppercase statement) are placed in the wrong loop
• If you are allowed to use it, I suggest to look at the Character class which has for example nice isUpperCase and isLowerCase methods

I leave the rest up to you since it is homework

Answer 3

This may not be what you are looking for but I thought you oughta know the real way to do this. You can use the java.lang.Character class's isUpperCase() to find aout about the case of the character. You can use isDigit() to differentiate between the numbers and letters(This is just FYI :) ). You can then do a toUpperCase() and then do the switch for vowels. This will improve your code quality.

Answer 4

You appear to have upper and lowercase back to front. A-Z would be upper, a-z would be lower. While not exactly efficient - with the inverted case exception, I think it should output correctly.

Answer 5

You don't need a for loop in your code.

Here is how you can re implement your method

• If input is between 'A' and 'Z' its uppercase
• If input is between 'a' and 'z' its lowercase
• If input is one of 'a,e,i,o,u,A,E,I,O,U' its Vowel
• Else Consonant

---

Edit:

Here is hint for you to proceed, Following code snippet gives int values for chars

System.out.println("a="+(int)'a');
System.out.println("z="+(int)'z');
System.out.println("A="+(int)'A');
System.out.println("Z="+(int)'Z');

Output

a=97
z=122
A=65
Z=90

Here is how you can check if a number x exists between two numbers say a and b

// x greater than or equal to a and x less than or equal to b
if ( x >= a && x <= b ) 

During comparisons chars can be treated as numbers

If you can combine these hints, you should be able to find what you want ;)

Answer 6

 Char input;

 if (input.matches("^[a-zA-Z]+$")) 
 {
     if (Character.isLowerCase(input))
     {
        // lowercase
     } 
     else
     { 
        // uppercase
     }

     if (input.matches("[^aeiouAEIOU]"))
     {
          // vowel
     }
     else 
     {
         // consonant
     }
 }
 else if (input.matches("^(0|[1-9][0-9]*)$"))
 {
       // number
 }
 else
 {
     // invalid
 }