How to get the current line number?

Question

I\'m trying to build a generic batch file that can tell errors with a line number, where the error occours.
But writing each line number in the code is a little bit anno

Answer 1

There is always way...
I found not the perfect solution, but a good workaround I can use.

I call a function which searches the own batch file(%~f0) with findStr, for the function parameter <uniqueID>, so this works only if these <uniqueID>'s are really unique for the whole batch.
The linenumber is get from the result of findstr /N.

In this sample:
6: call :getLineNumber errLine uniqueID4711 -2

The third parameter -2 is used to add an offset to the linenumber, so the result will be 4.

@echo off
SETLOCAL EnableDelayedExpansion

dir ... > nul 2> nul
if %errorlevel% NEQ 0 (
    call :getLineNumber errLine uniqueID4711    -2
    echo ERROR: in line !errLine!
)

set /a n=0xGH 2> nul
if %errorlevel% NEQ 0 (
    call :getLineNumber errLine uniqueID4712    -2
    echo ERROR: in line !errLine!
)
goto :eof

:::::::::::::::::::::::::::::::::::::::::::::
:GetLineNumber <resultVar> <uniqueID> [LineOffset]
:: Detects the line number of the caller, the uniqueID have to be unique in the batch file
:: The lineno is return in the variable <resultVar> add with the [LineOffset]
SETLOCAL
for /F " usebackq tokens=1 delims=:" %%L IN (`findstr /N "%~2" "%~f0"`) DO set /a lineNr=%~3 + %%L
( 
  ENDLOCAL
  set "%~1=%LineNr%"
  goto :eof
)