I\'m learning scala and mongodb at present and using the play! framework, so I\'m making all sorts of mistakes as I get my head around things. Currently I have a scala objec
I have the following
def service() = Action {
// connect
val collection = MongoConnection()("someDB")("someCollection")
// simply convert the result to a string, separating items with a comma
// this string goes inside an "array", and it's ready to hit the road
val json = "[%s]".format(
collection.find(someQuery).toList.mkString(",")
)
Ok(json).as("application/json")
}
You can try
com.mongodb.util.JSON.serialize(Alerts.list())
This should return a JSON array with your Alerts
I have what is a horrid solution as follows;
val currentAlerts = Alerts.list()
var jsonList : List[JsValue] = Nil
// Iterate over the DBObjects and use to String to convert each to JSON
// and then parse that back into the list so we can use toJson on it later.
// MAD, but works.
for (dbObject <- currentAlerts) {
jsonList ::= Json.parse(dbObject.toString)
}
val result = Json.toJson(jsonList)
Ok(result).as("application/json")
There must surely be a better way?