Create a ripple drawable without transparency

Question

I\'m a bit lost about how to properly use Ripple Drawable.

Let\'s say I have this drawable :

Answer 1

Forgot to answer my own question.

<?xml version="1.0" encoding="utf-8"?>
<ripple xmlns:android="http://schemas.android.com/apk/res/android"
   android:exitFadeDuration="@android:integer/config_shortAnimTime"
   android:color="@color/my_color" >

   <item android:id="@android:id/mask">
       <shape android:shape="rectangle" >
           <solid android:color="@android:color/holo_green_light" />
       </shape>
    </item>

</ripple>

The color in the item with the id "mask" is not displayed. It is used to tell the shape and bounds of the ripple effect. Without it, it can go outside the bounds of the view.

Answer 2

RippleDrawable is already a StateListDrawable (ie selector) - so you can just use a ripple drawable as your background (with a default state) - something like this:

<?xml version="1.0" encoding="utf-8"?>
<ripple xmlns:android="http://schemas.android.com/apk/res/android"
    android:color="@color/accent_color_light">
    <item android:id="@android:id/mask">
        <color android:color="@android:color/white" />
    </item>
    <item android:drawable="@android:color/white" />
</ripple>

the mask piece bounds the ripple (and, in reality, the above snippet, minus the colors and the last android:drawable which sets the non-pressed background) is the default list selector used in lollipop.