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How do i remove all linebreaks?

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情深已故
情深已故 2020-12-15 22:55

I have something like this:




   
      

        t
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  • 暖寄归人
    2020-12-15 23:11

    The following transformation:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>

<xsl:template match="*">
  <xsl:apply-templates select="@TEXT | node()"/>
</xsl:template>

<xsl:template match="node/@TEXT | text()">
  <xsl:if test="normalize-space(.)">
    <xsl:value-of select=
     "concat(normalize-space(.), '&#xA;')"/>
  </xsl:if>

  <xsl:apply-templates />
</xsl:template>

</xsl:stylesheet>

    when applied against this XML document

    <t>
<node TEXT="   txt A   "/>
<node TEXT="       txt X"/>
<node>
    <html>
        <p>        txt Y      </p>
    </html>
</node>
<node TEXT="txt B"/>
</t>

    produces the wanted result:

    txt A
    txt X
    txt Y
    txt B

    Do note the use of the standard XPath function normalize-space(), which strips off all leading and trailing spaces and replaces every sequence of other spaces with just one space.

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  • -上瘾入骨i
    2020-12-15 23:13

    You probably want

     <xsl:strip-space elements="node"/>

    explained here. And this article has a lot more details.

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