what is the best way to check variable type in javascript

Answer 1

The best way is using typeof

typeof "blahha" 

I made a function with help of jQuery library code, jQuery library type method github link .

var getType = (function() {

    var objToString = ({}).toString ,
        typeMap     = {},
        types = [ 
          "Boolean", 
          "Number", 
          "String",                
          "Function", 
          "Array", 
          "Date",
          "RegExp", 
          "Object", 
          "Error"
        ];

    for ( var i = 0; i < types.length ; i++ ){
        typeMap[ "[object " + types[i] + "]" ] = types[i].toLowerCase();
    };    

    return function( obj ){
        if ( obj == null ) {
            return String( obj );
        }
        // Support: Safari <= 5.1 (functionish RegExp)
        return typeof obj === "object" || typeof obj === "function" ?
            typeMap[ objToString.call(obj) ] || "object" :
            typeof obj;
    }
}());

You can call it as getType("Hello")

Answer 2

The best way is to use the typeof keyword.

typeof "hello" // "string"

The typeof operator maps an operand to one of six values: "string", "number", "object", "function", "undefined" and "boolean". The instanceof method tests if the provided function's prototype is in the object's prototype chain.

This Wikibooks article along with this MDN articles does a pretty good job of summing up JavaScript's types.

Answer 3

ES-Next version with support BigInt & Symbol

"use strict";

/**
 *
 * @author xgqfrms
 * @license MIT
 * @copyright xgqfrms
 * @created 2020-06-09
 * @modified
 *
 * @description js data type checker
 * @augments
 * @example
 * @link
 *
 */


const dataTypeChecker = (data, debug = false) => {
  const log = console.log;
  let result = ``;
  const typeString = Object.prototype.toString.call(data);
  result = typeString.replace(/\[object /gi, ``).replace(/\]/gi, ``);
  if(debug) {
    log(`true type`, result)
  }
  return result;
};



export default dataTypeChecker;

export {
  dataTypeChecker,
};

test

const dataTypeChecker = (data, debug = false) => {
  const log = console.log;
  let result = ``;
  const typeString = Object.prototype.toString.call(data);
  // const typeString = Object.prototype.toString.apply(data);
  result = typeString.replace(/\[object /gi, ``).replace(/\]/gi, ``);
  if(!debug) {
    log(`true type`, result)
  }
  return result;
};



const obj = {};
const func = () => {};


dataTypeChecker(NaN)
//"[object Number]"
dataTypeChecker(undefined)
//"[object Undefined]"
dataTypeChecker(true)
//"[object Boolean]"
dataTypeChecker({})
//"[object Object]"
dataTypeChecker(func)
//"[object Function]"
dataTypeChecker(obj)
//"[object Object]"
dataTypeChecker(Symbol())
//"[object Symbol]"
dataTypeChecker(null)
//"[object Null]"
dataTypeChecker(123)
//"[object Number]"
dataTypeChecker(BigInt(1n))
//"[object BigInt]"


// true type Number
// true type Undefined
// true type Boolean
// true type Object
// true type Function
// true type Object
// true type Symbol
// true type Null
// true type Number
// true type BigInt

Answer 4

use typeof();

example:

> typeof "foo"
"string"
> typeof true
"boolean"
> typeof 42
"number"

So you can do:

if(typeof bar === 'string') {
   //whatever
}

Keep in mind that, typeof is only good for returning the "primitive" types, number, boolean, object, string. You can also use instanceof to test if an object is of a specific type.

function MyObj(prop) {
  this.prop = prop;
}

var obj = new MyObj(10);

console.log(obj instanceof MyObj && obj instanceof Object); // outputs true

Answer 5

The getVarType method (below) works for almost all variables. Check out this fiddle. It first uses the very fast typeof for cases where the results are reliable. Then it uses a more expensive toString method for other cases. Finally, if it is dealing with a named object (as returned by Firefox for objects like document.location) it checks for Array-like objects and reports them as arrays.

In comparison, typeof is embarrassingly poor. typeof([]) returns 'object', typeof(new Number()) returns object. It also returns 'object' for many other variables that aren't (for practical purposes) objects. See the fiddle results for a comparison.

  // Begin public utility /getVarType/
  // Returns 'Function', 'Object', 'Array',
  // 'String', 'Number', 'Null', 'Boolean', or 'Undefined'
  //
  getVarType = (function () {
    var typeof_map = {
      'undefined' : 'Undefined',
      'boolean'   : 'Boolean',
      'number'    : 'Number',
      'string'    : 'String',
      'function'  : 'Function',

      'Undefined' : 'Undefined',
      'Null'      : 'Null',
      'Boolean'   : 'Boolean',
      'Number'    : 'Number',
      'String'    : 'String',
      'Function'  : 'Function',
      'Array'     : 'Array',
      'StyleSheetList' : 'Array'
    };

    return function( data ) {
      var type, type_str;

      if ( data === null      ) { return 'Null'; }
      if ( data === undefined ) { return 'Undefined'; }

      type     = typeof( data );
      type_str = typeof_map[ type ];

      if ( type_str ) { return type_str; }

      type = {}.toString.call( data ).slice( 8, -1 );
      return typeof_map[ type ]
        || ( data instanceof Array ? 'Array' :
        ( data.propertyIsEnumerable(0) && data.length !== undefined
          ? 'Array' : 'Object' )
        );
    };
  }());
  // End public utility /getVarType/

The only possible failure mode happens if you are testing a named array that is empty (e.g. an empty enumerable DOM object besides the StyleSheetList). But on could add those to the type_of_map as needed.

I hope that helps!

Answer 6

typeof capitalized == 'string'