I\'m using C# and I need to generate a random 10 digit number. So far, I\'ve only had luck finding examples indicating min maximum value. How would i go about generating a r
(1000000000,9999999999) is not random - you're mandating that it cannot begin with a 1, so you've already cut your target base by 10%.
Random is a double, so if you want a integer, multiply it by 1,000,000,000, then drop the figures after the decimal place.
private static Random random = new Random((int)DateTime.Now.Ticks);//thanks to McAden
public long LongBetween(long maxValue, long minValue)
{
return (long)Math.Round(random.NextDouble() * (maxValue - minValue - 1)) + minValue;
}
Here is a simple solution using format string:
string r = $"{random.Next(100000):00000}{random.Next(100000):00000}";
Random 10 digit number (with possible leading zeros) is produced as union of two random 5 digit numbers. Format string "00000" means leading zeros will be appended if number is shorter than 5 digits (e.g. 1 will be formatted as "00001").
For more about the "0" custom format specifier please see the documentation.
If you want ten digits but you allow beginning with a 0 then it sounds like you want to generate a string, not a long integer.
Generate a 10-character string in which each character is randomly selected from '0'..'9'.
To get the any digit number without any loop, use Random.Next with the appropriate limits [100...00, 9999...99].
private static readonly Random _rdm = new Random();
private string PinGenerator(int digits)
{
if (digits <= 1) return "";
var _min = (int)Math.Pow(10, digits - 1);
var _max = (int)Math.Pow(10, digits) - 1;
return _rdm.Next(_min, _max).ToString();
}
This function calculated the lower and the upper bounds of the nth digits number.
To generate the 10 digit number use it like this:
PinGenerator(10)
// ten digits
public string CreateRandomNumber
{
get
{
//returns 10 digit random number (Ticks returns 16 digit unique number, substring it to 10)
return DateTime.UtcNow.Ticks.ToString().Substring(8);
}
}