Equivalent of Java triple shift operator (>>>) in C#?

Question

What is the equivalent (in C#) of Java\'s >>> operator?

(Just to clarify, I\'m not referring to the >> and <<

Answer 1

n >>> s in Java is equivalent to TripleShift(n,s) where:

    private static long TripleShift(long n, int s)
    {
        if (n >= 0)
            return n >> s;
        return (n >> s) + (2 << ~s);
    }

Answer 2

Upon reading this, I hope my conclusion of use as follows is correct. If not, insights appreciated.

Java

i >>>= 1;

C#:

i = (int)((uint)i >> 1);

Answer 3

For my VB.Net folks

The suggested answers above will give you overflow exceptions with Option Strict ON

Try this for example -100 >>> 2 with above solutions:

The following code works always for >>>

Function RShift3(ByVal a As Long, ByVal n As Integer) As Long
        If a >= 0 Then
            Return a >> n
        Else
            Return (a >> n) + (2 << (Not n))
        End If
End Function

Answer 4

In C#, you can use unsigned integer types, and then the << and >> do what you expect. The MSDN documentation on shift operators gives you the details.

Since Java doesn't support unsigned integers (apart from char), this additional operator became necessary.

Answer 5

There is no >>> operator in C#. But you can convert your value like int,long,Int16,Int32,Int64 to unsigned uint, ulong, UInt16,UInt32,UInt64 etc.

Here is the example.

    private long getUnsignedRightShift(long value,int s)
    {
        return (long)((ulong)value >> s);
    }

Answer 6

Java doesn't have an unsigned left shift (<<<), but either way, you can just cast to uint and shfit from there.

E.g.

(int)((uint)foo >> 2); // temporarily cast to uint, shift, then cast back to int