PHP: what's an alternative to empty(), where string “0” is not treated as empty? [duplicate]

Answer 1

function isempty(&$var) {
    return empty($var) || $var === '0';
}

The key is the & operator, which passes the variable by reference, creating it if it doesn't exist.

Answer 2

if ((isset($var) && $var === "0") || !empty($var))
{

}

This way you will enter the if-construct if the variable is set AND is "0", OR the variable is set AND not = null ("0",null,false)

Answer 3

function Void($var)
{
    if (empty($var) === true)
    {
        if (($var === 0) || ($var === '0'))
        {
            return false;
        }

        return true;
    }

    return false;
}

Answer 4

This should do what you want:

function notempty($var) {
    return ($var==="0"||$var);
}

Edit: I guess tables only work in the preview, not in actual answer submissions. So please refer to the PHP type comparison tables for more info.

notempty("")       : false
notempty(null)     : false
notempty(undefined): false
notempty(array())  : false
notempty(false)    : false
notempty(true)     : true
notempty(1)        : true
notempty(0)        : false
notempty(-1)       : true
notempty("1")      : true
notempty("0")      : true
notempty("php")    : true

Basically, notempty() is the same as !empty() for all values except for "0", for which it returns true.

---

Edit: If you are using error_reporting(E_ALL), you will not be able to pass an undefined variable to custom functions by value. And as mercator points out, you should always use E_ALL to conform to best practices. This link (comment #11) he provides discusses why you shouldn't use any form of error suppression for performance and maintainability/debugging reasons.

See orlandu63's answer for how to have arguments passed to a custom function by reference.

Answer 5

The answer to this is that it isn't possible to shorten what I already have.

Suppressing notices or warnings is not something I want to have to do, so I will always need to check if empty() or isset() before checking the value, and you can't check if something is empty() or isset() within a function.

Answer 6

If ($var != null)