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What's The Correct Way To Set Src Attribute In JQuery?

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日久生厌
日久生厌 2020-12-15 16:07

Suppose I have the following HTML:

I would like to switch the src to bar2.jpg

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5条回答
  • 夕颜
    2020-12-15 16:26

    Just do .attr('src', 'foo') because you're assigning a src regardless. Only remove the attribute if you don't need it entirely.

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  • 悲&欢浪女
    2020-12-15 16:27

    When you do this:

    $("#foo").attr("src", "bar2.jpg");

    The previous src is replaced.

    So you don't need:

    $("#foo").removeAttr("src");

    You can confirm it out here

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  • 迷失自我
    2020-12-15 16:31

    Even for mediaelement player have:

      $("#player5").attr("poster", "/images/poster/Azadi.jpg");
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  • 挽巷
    2020-12-15 16:35

    The first wey is just fine, no reason to remove it first.

    $("#foo").attr("src", "bar2.jpg");

    $.attr serves both to get the existing attribute and to change it (depending on whether theres one or two arguments). Your situation is exactly what he second functionality is intended for, and the attribute 'src' is not special.

    http://api.jquery.com/attr/

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  • 迷失自我
    2020-12-15 16:36 
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<style>
.main{
    position:relative;
}
.second{
position:absolute;
top:20px;
left:720px;
}
.third{
    position:absolute;
top:290px;
left:720px;
}
.fourth{
    position:absolute;
top:100px;
left:1030px;
}
.firstarrow{
    position:absolute;
top:20px;
left:1100px;
}
.secondarrow{
    position:absolute;
top:20px;
left:1030px;
}
</style>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script> 
$(document).ready(function(){
  $(".firstarrow").on('click', function() {
   var pos1 = $('.first img').attr('src');
   var pos2 = $('.second img').attr('src');
   var pos3 = $('.third img').attr('src');
   var pos4 = $('.fourth img').attr('src');
   $('.third img').attr('src', pos1);
   $('.fourth img').attr('src', pos3);
   $('.second img').attr('src', pos4);
   $('.first img').attr('src', pos2);
});

  $(".secondarrow").on('click', function() {
   var pos1 = $('.first img').attr('src');
   var pos2 = $('.second img').attr('src');
   var pos3 = $('.third img').attr('src');
   var pos4 = $('.fourth img').attr('src');
   $('.third img').attr('src', pos4);
   $('.fourth img').attr('src', pos2);
   $('.second img').attr('src', pos1);
   $('.first img').attr('src', pos3);
});

});
</script>

</head>

<body>
<div class="main">
<div class="first">
<img src="img1.jpg" alt="" width="700" height="511" />
</div>
<div class="second">
<img src="img2.jpg" alt="" width="300" height="250" />
</div>
<div class="third">
<img src="img3.jpg" alt="" width="300" height="250" />
</div>
<div class="fourth">
<img src="img4.jpg" align="" width="300" height="400"  />
</div>
<a href="#"><div class="firstarrow"><img src="ar1.jpg" width="48" height="48" /></div></a>
<a href="#"><div class="secondarrow"><img src="ar2.jpg" width="48" height="48" /></div></a>
</div>

</body>
</html>
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