How to create tar for files older than 7 days using linux shell scripting

Question

I\'m writing shell script to backup files older than 7 days. Here is my code. But i\'m not getting expected result. Can anyone correct me?

#!/bin/bash
# Back         


        

Answer 1

Replace your find command with this and try again,

find /var/log -type f -mtime +7 

Answer 2

This will work:

#!/bin/bash
files=()
while IFS=  read -r -d $'\0'; do
    files+=("$REPLY")
done < <(find /var/log/ -mtime +7 -print0)
tar cvfz backup.tar.gz "${files[@]}"

Note the use of "${files[@]}" as opposed to ${files[*]}. "${files[@]}" will expand to provide tar with one argument per file name and will work even if the file names contain spaces, tabs, or newlines. By contrast, after the shell expands ${files[*]}, it will perform word splitting, potentially mangling your file names.

For a detailed explanation of the loop used to create the files array, see: How can I store find command result as arrays in Bash

All files and directories produced by the command find /var/log/ -mtime +7 will be included in the tar file. To include only files, not directories, see Skynet's answer.

To archive logs from the seven most recent days

Only one character need change:

#!/bin/bash
files=()
while IFS=  read -r -d $'\0'; do
    files+=("$REPLY")
done < <(find /var/log/ -mtime -7 -print0)
tar cvfz backup.tar.gz "${files[@]}"

This works because find interprets numeric arguments as follows:

Numeric arguments can be specified as
+n for greater than n,
-n for less than n,
n for exactly n.

Thus, -mtime +7 means greater than 7 days old while -mtime -7 means less than 7. Note that find will ignore fractional parts. Thus +7 will include 8 days old but not 7.5 days old. See man find for details.