How can I check JavaScript arrays for empty strings?

Question

I need to check if array contains at least one empty elements. If any of the one element is empty then it will return false.

Example:

var my_arr = ne         


        

Answer 1

You can check by looping through the array with a simple for, like this:

function NoneEmpty(arr) {
  for(var i=0; i<arr.length; i++) {
    if(arr[i] === "") return false;
  }
  return true;
}

You can give it a try here, the reason we're not using .indexOf() here is lack of support in IE, otherwise it'd be even simpler like this:

function NoneEmpty(arr) {
  return arr.indexOf("") === -1;
}

But alas, IE doesn't support this function on arrays, at least not yet.

Answer 2

For Single dimensional Array

array.some(Boolean)

For Multi dimensional Array

array.some(row => row.some(Boolean))

Answer 3

my_arr.includes("")

This returned undefined instead of a boolean value so here's an alternative.

function checkEmptyString(item){
     if (item.trim().length > 0) return false;
     else return true;
    };
    
function checkIfArrayContainsEmptyString(array) {
  const containsEmptyString = array.some(checkEmptyString);
  return containsEmptyString;
};
    
console.log(checkIfArrayContainsEmptyString(["","hey","","this","is","my","solution"]))
// *returns true*

console.log(checkIfArrayContainsEmptyString(["yay","it","works"]))
// *returns false*

Answer 4

function containsEmpty(a) {
    return [].concat(a).sort().reverse().pop() === "";
}
alert(containsEmpty(['1','','qwerty','100'])); // true
alert(containsEmpty(['1','2','qwerty','100'])); // false

Answer 5

You have to check in through loop.

function checkArray(my_arr){
   for(var i=0;i<my_arr.length;i++){
       if(my_arr[i] === "")   
          return false;
   }
   return true;
}

Answer 6

Nowadays we can use Array.includes

my_arr.includes("")

Returns a Boolean