DataFrame I have:
A B C
2012-01-01 1 2 3
2012-01-05 4 5 6
2012-01-10 7 8 9
2012-01-15 10 11 12
What
You might want to go directly do the index:
i = frame.index.searchsorted(date)
frame.ix[frame.index[i]]
A touch verbose but you could put it in a function. About as good as you'll get (O(log n))
Couldn't resist answering this, even though the question was asked, and answered, in 2012, by Wes himself, and again in 2015, by ajsp. Yes, besides 'truncate', you can also use get_loc with the option 'nearst'
df.iloc[df.index.get_loc(datetime.datetime(2016,02,02),method='nearest')]
Couldn't resist answering this, even though the question was asked, and answered, in 2012, by Wes himself. Yes, just use truncate.
df.truncate(before='2012-01-07')