How to find the length of argv[] in C

Question

#include 
#include 
#include 

int main(int argc, char *argv[]){
    int fir; //badly named loop variable
    char *in         


        

Answer 1

//Task = get length of argv
    string text=*argv; //assigning charValue to string variable "text"
    int l=text.length(); //getting the length of the string & assigning to variale "l"

    //this loop just outputs result on the screen
    for (int i=0; i<l; i++) { 
        cout << *(*argv+i) << flush;
    }

Answer 2

Not sure why no one has suggested changing strlen to refer to a specific entry in the array of pointers to char?

 strlen(argv[0])     // also, 1, 2, up to (argc - 1)

Also, http://www.cdecl.org/ helps in confirming that the char *argv[] statement is: declare argv as array of pointer to char