I\'m new to React, just have a question on setState method. Let\'s say we have a component:
class MyApp extends React.Component {
state = {
count: 3
If you call a function multiple times to change the value of a state property in a single render()
function call then the updated value will not go over between the different calls without prevState mechanism.
second(){
this.setState({ // no previous or latest old state passed
sec:this.state.sec + 1
}, ()=>{
console.log("Callback value", this.state.sec)
})
}
fiveSecJump(){ // all this 5 call will call together
this.second() // this call found sec = 0 then it will update sec = 0 +1
this.second() // this call found sec = 0 then it will update sec = 0 +1
this.second() // this call found sec = 0 then it will update sec = 0 +1
this.second() // this call found sec = 0 then it will update sec = 0 +1
this.second() // this call found sec = 0 then it will update sec = 0 +1
}
render() {
return (
<div>
<div> Count - {this.state.sec}</div>
<button onClick ={()=>this.fiveSecJump()}>Increment</button>
</div>
)
}
Finally sec value will be 1, because calls are async, not like high-level programming language like c++/c# or java where there is always a main function which maintains the main thread.
Therefore if you want to have fiveSecJump()
function to work properly you have to help it by passing it an arrow function. prevState. prevState is not a keyword or member function, you can write any word here like oldState, stackTopState, lastState. It will convert to a generic function which will do your desired work.
class Counter extends Component {
constructor(props){
super(props)
this.state = {
sec:0
}
}
second(){
this.setState(prevState =>({
sec:prevState.sec + 1
}))
}
fiveSecJump(){
this.second() // this call found sec = 0 then it will update sec = 0 +1
this.second() // this call found sec = 1 then it will update sec = 1 +1
this.second() // this call found sec = 2 then it will update sec = 2 +1
this.second() // this call found sec = 3 then it will update sec = 3 +1
this.second() // this call found sec = 4 then it will update sec = 4 +1
}
render() {
return (
<div>
<div> Count - {this.state.sec}</div>
<button onClick ={()=>this.fiveSecJump()}>Increment</button>
</div>
)
}
}
export default Counter
here iseveryone know just state:prevstate.counter+1.. we can also do this with state:this.state.counter+1. This is not the way i think to use prevstate. i have problem in array when i push into existing state it allow me but second time it prevent changes
Both signatures can be used, the only difference is that if you need to change your state based on the previous state you should use this.setState(function)
which will provide you a snapshot(prevState
) from the previous state. But if the change does not rely on any other previous value, then a shorter version is recommended this.setState({prop: newValue})
this.setState(prevState =>{
return{
...prevState,
counter : prevState.counter +1
}
})
this.setState({counter : 2})
class MyApp extends React.Component {
state = {
count: 0
};
Increment = () => {
this.setState(prevState => ({
count: prevState.count + 1
}));
this.setState(prevState => ({
count: prevState.count + 1
}));
this.setState(prevState => ({
count: prevState.count + 1
}));
this.setState(prevState => ({
count: prevState.count + 1
}));
};
IncrementWithoutPrevState = () => {
this.setState(() => ({
count: this.state.count + 1
}));
this.setState(() => ({
count: this.state.count + 1
}));
this.setState(() => ({
count: this.state.count + 1
}));
this.setState(() => ({
count: this.state.count + 1
}));
};
render() {
return (
<div>
<button onClick={this.IncrementWithoutPrevState}>
Increment 4 times without PrevState
</button>
<button onClick={this.Increment}>
Increment 4 times with PrevState
</button>
<h1>Count: {this.state.count}</h1>
</div>
);
}
}
I just made an example for you to give an idea what is meant by "React may batch multiple setState()..." and why we should use prevState in the above scenario.
First, try to guess what should the result of Count
when you click both buttons... If you think the count
will be incremented by 4 on click of both buttons then it's not right guess ;)
Why? because in IncrementWithoutPrevState
method since there are multiple setState
calls, so React batched all those calls and updates the state
only in the last call of setState
in this method, so at the time of last call to setState
in this method this.state.count
is not yet updated and its value is still the same that was before entering into IncrementWithoutPrevState
method so the resultant state will contain count
incremented by 1.
Now on the other hand side if we analyze the Increment
method:
Again there are multiple setState
calls and React batched them all that means the actual state will be updated in the last call of setState
but the prevState
will always contain the modified state
in the recent setState
call. As previousState.count
value has already been incremented 3 times till the last call of setState
so the resultant state
will contain the count value incremented by 4.