Adding a name to the “from” field in SendGrid in Node.js

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I want to add a name to my \"from\" field using the SendGrid API, but I do not know how to do this. I tried setting the \"from\" parameter in sendgrid.send to <

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春和景丽

2020-12-15 06:04
Although the updated use cases don't include the from key

https://github.com/sendgrid/sendgrid-nodejs/blob/master/docs/use-cases/flexible-address-fields.md

This one worked for me
```
  to: 'user@userdomain.com',
  from: {
      name: 'Sender'
      email: 'me@mydomain.com',
  },
  subject: 'Hello World',
  html: `<html><p>Hello World</p></html>`
});
```
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暖寄归人

2020-12-15 06:08

You can set the from parameter in a couple of ways:

var SendGrid = require('sendgrid').SendGrid;
var sendgrid = new SendGrid(user, key);
sendgrid.send({
  to: 'you@yourdomain.com',
  from: 'example@example.com',  // Note that we set the `from` parameter here
  fromname: 'Name', // We set the `fromname` parameter here
  subject: 'Hello World',
  text: 'My first email through SendGrid'
}, function(success, message) {
  if (!success) {
    console.log(message);
  }
});

or you can create an Email object and fill in the stuff on that:

var Email = require('sendgrid').Email;
var email = new Email({
  to: 'you@yourdomain.com',
  from: 'example@example.com',
  fromname: 'Name',
  subject: 'What was Wenger thinking sending Walcott on that early?',
  text: 'Did you see that ludicrous display last night?'
});

sendgrid.send(email, function() { 
  // ... 
});

You might want to take a few minutes and go over the README document on the Github page. It has pretty detailed info on how to use the library and the various features it offers.

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梦毁少年i

2020-12-15 06:11

Updated example with the syntax used in the latest version of the Sendgrid Node.js library.

sendgrid.send({
  to: 'you@yourdomain.com',
  from: {
      email: 'example@example.com',
      name: 'Sender Name'
  },
  subject: 'Hello World',
  text: 'My first email through SendGrid'
});

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夕颜

2020-12-15 06:15
If you are using the nodejs Helper library, use the following arguments:
```
from_email = new helper.Email("email@domain.com", "Email Name");
```
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