Comparison to `None` will result in an elementwise object

Question

Apparantly it will (in the \'future\') not be possible anymore to use the following:

import numpy as np
np.array([0,1,2]) == None
> False
> FutureWarni         


        

Answer 1

You are looking for is:

if a is None:
    a = something else

The problem is that, by using the == operator, if the input element a is a numpy array, numpy will try to perform an element wise comparison and tell you that you cannot compare it.

For a a numpy array, a == None gives error, np.all(a == None) doesn't (but does not do what you expect). Instead a is None will work regardless the data type of a.