Test empty string in mongodb and pymongo

Question

Here is my data structure.

[{
\"name\": \"David\",
\"lastname\": \"\",
},
{
\"name\": \"Angela\"
}]

\"lastname\" is sometimes present and

Answer 1

Facing this problem I thought in another solution:

db.collection.find({"lastname": {"$gte": " "}})

With this I could get only the not empty strings, also ignoring null and not existent field, because any printable value (ASCII) has a greater value than space (32).

https://en.wikipedia.org/wiki/ASCII

Answer 2

db.collection.find({"lastname" : {"$exists" : true, "$ne" : ""}})

In the mongo shell (id's omitted to save space)

> db.collection.find()
  { "name" : "Angela" }
  { "name" : "David", "lastname" : "" }
  { "name" : "Kyle",  "lastname" : "Test" }
  { "name" : "John",  "lastname" : null }

> db.collection.find({"lastname" : {"$exists" : true, "$ne" : ""}})
  { "name" : "Kyle", "lastname" : "Test" }
  { "name" : "John",  "lastname" : null }

In case you also want to filter out matches against null values you need to adjust the criteria as follows (we can also get rid of $exists as "$ne": null takes care of this)

> db.collection.find({$and:[{"lastname": {"$ne": null}}, {"lastname": {"$ne": ""}}]})
  { "name" : "Kyle", "lastname" : "Test" }

Answer 3

You can use a regex query:

db.test.find({ "lastname": /(.|\s)*\S(.|\s)*/ })

This regex matches strings beginning or ending with 0 or N whitespaces (.|\s) and it have to be one or more non-whitespaces \S in the middle.