Could someone explain how exactly the copy
method for Kotlin data classes work? It seems like for some members, a (deep) copy is not actually created and the re
There is a way to make a deep copy of an object in Kotlin (and Java): serialize it to memory and then deserialize it back to a new object. This will only work if all the data contained in the object are either primitives or implement the Serializable interface
Here is an explanation with sample Kotlin code https://rosettacode.org/wiki/Deepcopy#Kotlin
import java.io.Serializable
import java.io.ByteArrayOutputStream
import java.io.ByteArrayInputStream
import java.io.ObjectOutputStream
import java.io.ObjectInputStream
fun <T : Serializable> deepCopy(obj: T?): T? {
if (obj == null) return null
val baos = ByteArrayOutputStream()
val oos = ObjectOutputStream(baos)
oos.writeObject(obj)
oos.close()
val bais = ByteArrayInputStream(baos.toByteArray())
val ois = ObjectInputStream(bais)
@Suppress("unchecked_cast")
return ois.readObject() as T
}
Note: This solution should also be applicable in Android using the Parcelable interface instead of the Serializable. Parcelable is more efficient.
As @Ekeko said, the default copy()
function implemented for data class is a shallow copy which looks like this:
fun copy(a: Int = this.a, bar: Bar = this.bar, list: MutableList<Int> = this.list)
To perform a deep copy, you have to override the copy()
function.
fun copy(a: Int = this.a, bar: Bar = this.bar.copy(), list: MutableList<Int> = this.list.toList()) = Foo(a, bar, list)
Building on a previous answer, an easy if somewhat inelegant solution is to use the kotlinx.serialization facility. Add the plugin to build.gradle
as per the docs, then to make a deep copy of an object, annotate it with @Serializable
and add a copy method which converts the object to a serialised binary form, then back again. The new object will not reference any objects in the original.
import kotlinx.serialization.Serializable
import kotlinx.serialization.cbor.Cbor
@Serializable
data class DataClass(val yourData: Whatever, val yourList: List<Stuff>) {
var moreStuff: Map<String, String> = mapOf()
fun copy(): DataClass {
return Cbor.load(serializer(), Cbor.dump(serializer(), this))
}
This won't be as fast as a handwritten copy function, but it does not require updating if the object is changed, so is more robust.
Beware of those answers who are just copying list reference from an old object into the new one. Only quick way of deep copying I have found is to either serialize/deserialize objects i.e. convert the objects into JSON and then transform them back to POJO. If you are using GSON, here is the piece of code:
class Foo {
fun deepCopy() : Foo {
return Gson().fromJson(Gson().toJson(this), this.javaClass)
}
}
The copy
method of Kotlin is not supposed to be a deep copy at all. As explained in the reference doc (https://kotlinlang.org/docs/reference/data-classes.html), for a class such as:
data class User(val name: String = "", val age: Int = 0)
the copy
implementation would be:
fun copy(name: String = this.name, age: Int = this.age) = User(name, age)
So as you can see, it's a shallow copy. The implementations of copy
in your specific cases would be:
fun copy(a: Int = this.a, bar: Bar = this.bar, list: MutableList<Int> = this.list) = Foo(a, bar, list)
fun copy(x: Int = this.x) = Bar(x)