how to parse hex or decimal int in Python [duplicate]

Answer 1

If you are doing a lot of go between with different number systems, the bitstring library make a lot of binary/Hex operations easier. It also supports string interpretation:

http://pythonhosted.org/bitstring/

Answer 2

Base 16 to 10 (return an integer):

>>> int('0x123', 16)
291

Base 10 to 16 (return a string):

>>> hex(291)
'0x123'

Answer 3

This is a simpler version which works like a charm. Returns string since hex() returns the same type:

def itoh(int): return hex(int)[2:]

Answer 4

Something like this might be what you're looking for.

def convert( aString ):
    if aString.startswith("0x") or aString.startswith("0X"):
        return int(aString,16)
    elif aString.startswith("0"):
        return int(aString,8)
    else:
        return int(aString)

Answer 5

int("0x123", 0)

(why doesn't int("0x123") do that?)