SQL query to find Nth highest salary

Question

I am referring to following query to find Nth highest salary of a employee.

select sal from emp t where &n = (select count(sal) from (select distinct sal         


        

Answer 1

To get the nth highest salary value just put the value of 'N'.

Select Min(Salary) From (Select Top N * From Table_Name Order by Salary Desc);

Answer 2

In the database record data entries like

employ_id    NAME     salary
101          Henry    24000
102          Smith    24000
105          Roy      17000  
106          Robbin   15000 
702          Mac      2500
708          Bill     2100
709          Kane     2000
710          Ted      2000

here Some of employees having same salary then how to calculate nth (highest/lowest)salary

for the calculation of 3rd highest salary

select * from emloyees where salary in (select salary from (select rownum rank , salary from (select distinct salary from employees order by salary **desc**)) where rank =3;

---

ans = 15000

similarly to calculate 3rd lowest salary Type same Query with a small change instead of desc type asc

select * from emloyees where salary in (select salary from (select rownum rank , salary from (select distinct salary from employees order by salary **asc**)) where rank =3;

Hope This will help you

Answer 3

select sal 
from (
  select sal, 
         dense_rank() over (order by sal desc) as rnk
) t
where rnk = 5;

Replace where rnk = 5 with whatever "nth" you want.

Answer 4

There are so many ways to achieve this:-

1)

 Select Top(1) sal from emp 
    where sal not in (select DISTINCT top(n-1) sal from emp order by sal desc)

2)

select salary     
          from (
           select salary,
           roe_number() over (order by salary ) as row from emp
          ) emp1
  where row= n;

• This query will not work if multiple rows have the same values one after another.

3)

select salary     
              from (
               select salary,
               dense_rank() over (order by salary ) as row from emp
              ) emp1
      where row= n;

• This will create a unique row number for all unique salary amounts.

4)

 Select Min(sal) From 
       (Select DISTINCT Top n * From emp Order by sal Desc)as emp1;

5)

   SELECT * FROM emp Emp1
            WHERE (n-1) = (
                             SELECT COUNT(DISTINCT(Emp2.Sal))
                             FROM emp Emp2
                             WHERE Emp2.Sal > Emp1.Sal)

Answer 5

Change nth highest salary value just put the value of 'N'

SELECT e1.EmployeeName, e1.EmployeeSalary from Employee e1
where N = (
select COUNT(e2.EmployeeSalary) from Employee e2 where e2.EmployeeSalary >= e1.EmployeeSalary)

Answer 6

Query:

select 
    ename  
    ,sal  
    ,dense_rank() over (order by sal desc) ranking  
from   emp;  

output:

ENAME   SAL   RANKING
KING    5000    1   
FORD    3000    2  
SCOTT   3000    2  
JONES   2975    3  
CLARK   2850    4  
BLAKE   2850    4  
ALLEN   1600    5  

Wrap a filter around and pick out the Nth highest salary, say the 4th highest salary.

Query:

select *  
from  
(  
  select ename  
        ,sal  
        ,dense_rank() over (order by sal desc) ranking  
  from   emp  
)  
where ranking = 4 -- Replace 4 with any value of N  

output:

ENAME  SAL  RANKING
BLAKE  2850     4  
CLARK  2850     4