How would I parse the XML file in R and carry out basic Statistics Analysis on the data

Question

I am trying to parse the XML file in R, so that I can analysis the data. I am trying to get the mean and standard deviation of the price. Also I would like to be able to get

Answer 1

In

z <- strptime ("HH:MM:SS.ms, "%H:%m:%S.%f")

you miss a closing " so it is invalid syntax.

Next, the data is non-standard as we would use a dot for seconds.subseconds, ie 12:23:34.567 to denote a timestamp. The milliseconds can be parsed this way

> ts <- "12:00:00.050"
> strptime(ts, "%H:%M:%OS")
[1] "2010-07-09 12:00:00 CDT"
> 

So you not only need to get it out of XML first, but also need to convert the string. Else, you can parse the string an fill a POSIXlt time structure 'by hand'.

Postscriptum: Forgot to mention that you need to enable printing of sub-second times:

> options("digits.secs"=3)         # shows milliseconds (three digits)
> strptime(ts, "%H:%M:%OS")
[1] "2010-07-09 12:00:00.05 CDT"   # suppresses trailing zero
> 

Postscriptum 2: You are also in luck with respect to your file thanks to the XML package:

> library(XML)
> xmlToDataFrame("c:/Temp/foo.xml")     # save your data as c:/Temp/foo.xml
      timeStamp   Price
1   12:00:00:01   25.02
2   12:00:00:02      15
3  12:00:00:025   15.02
4  12:00:00:031   18.25
5  12:00:00:039   18.54
6  12:00:00:050   16.52
7   12:00:01:01   17.50
> 

Answer 2

For more complex XML data, it might useful to use the XML package.

library(XML)

check <- xmlInternalTreeParse("/PathToXMLFile/checkXML.xml")
xpathSApply(check, "//timeStamp", xmlValue)
## [1] " 12:00:00:01"  " 12:00:00:02"  " 12:00:00:025" " 12:00:00:031"
## [5] " 12:00:00:039" " 12:00:00:050" " 12:00:01:01"