Force priority of go select statement

Question

I have the following piece of code:

func sendRegularHeartbeats(ctx context.Context) {
    for {
        select {
        case <-ctx.D         


        

Answer 1

The accepted answer has a wrong suggestion:

func sendRegularHeartbeats(ctx context.Context) {
    ticker := time.NewTicker(time.Second)
    defer ticker.Stop()

    for {
        //first select 
        select {
        case <-ctx.Done():
            return
        default:
        }

        //second select
        select {
        case <-ctx.Done():
            return
        case <-ticker.C:
            sendHeartbeat()
        }
    }
}

This doesn't help, because of the following scenario:

1. both channels are empty
2. first select runs
3. both channels get a message concurrently
4. you are in the same probability game as if you haven't done anything in the first select

An alternative but still imperfect way is to guard against concurrent Done() events (the "wrong select") after consuming the ticker event i.e.

func sendRegularHeartbeats(ctx context.Context) {
    ticker := time.NewTicker(time.Second)
    defer ticker.Stop()

    for {            
        //select as usual
        select {
        case <-ctx.Done():
            return
        case <-ticker.C:
            //give priority to a possible concurrent Done() event non-blocking way
            select {
              case <-ctx.Done():
              return
            default:
            }
            sendHeartbeat()
        }
    }
}

Caveat: the problem with this one is that it allows for "close enough" events to be confused - e.g. even though a ticker event arrived earlier, the Done event came soon enough to preempt the heartbeat. There is no perfect solution as of now.

Answer 2

Note beforehand:

Your example will work as you intend it to, as if the context is already cancelled when sendRegularHeartbeats() is called, the case <-ctx.Done() communication will be the only one ready to proceed and therefore chosen. The other case <-time.After(1 * time.Second) will only be ready to proceed after 1 second, so it will not be chosen at first. But to explicitly handle priorities when multiple cases might be ready, read on.

---

Unlike the case branches of a switch statement (where the evaluation order is the order they are listed), there is no priority or any order guaranteed in the case branches of a select statement.

Quoting from Spec: Select statements:

If one or more of the communications can proceed, a single one that can proceed is chosen via a uniform pseudo-random selection. Otherwise, if there is a default case, that case is chosen. If there is no default case, the "select" statement blocks until at least one of the communications can proceed.

If more communications can proceed, one is chosen randomly. Period.

If you want to maintain priority, you have to do that yourself (manually). You may do it using multiple select statements (subsequent, not nested), listing ones with higher priority in an earlier select, also be sure to add a default branch to avoid blocking if those are not ready to proceed. Your example requires 2 select statements, first one checking <-ctx.Done() as that is the one you want higher priority for.

I also recommend using a single time.Ticker instead of calling time.After() in each iteration (time.After() also uses a time.Ticker under the hood, but it doesn't reuse it just "throws it away" and creates a new one on the next call).

Here's an example implementation:

func sendRegularHeartbeats(ctx context.Context) {
    ticker := time.NewTicker(time.Second)
    defer ticker.Stop()

    for {
        select {
        case <-ctx.Done():
            return
        default:
        }

        select {
        case <-ctx.Done():
            return
        case <-ticker.C:
            sendHeartbeat()
        }
    }
}

This will send no heartbeat if the context is already cancelled when sendRegularHeartbeats() is called, as you can check / verify it on the Go Playground.

If you delay the cancel() call for 2.5 seconds, then exactly 2 heartbeats will be sent:

ctx, cancel := context.WithCancel(context.Background())
go sendRegularHeartbeats(ctx)
time.Sleep(time.Millisecond * 2500)
cancel()
time.Sleep(time.Second * 2)

Try this one on the Go Playground.

Answer 3

If it is absolutely critical to maintain that priority of operations, you can:

• Consume from each channel in a separate goroutine
• Have each of those goroutines write a message to a shared third channel indicating its type
• Have a third goroutine consume from that channel, reading the messages it receives to determine if it is a tick and should sendHeartbeat or if it is a cancel and it should exit

This way, messages received on the other channels will (probably - you can't guarantee order of execution of concurrent routines) come in on the third channel in the order they're triggered, allowing you to handle them appropriately.

However, it's worth noting that this is probably not necessary. A select does not guarantee which case will execute if multiple cases succeed simultaneously. That is probably a rare event; the cancel and ticker would both have to fire before either was handled by the select. The vast majority of the time, only one or the other will fire at any given loop iteration, so it will behave exactly as expected. If you can tolerate rare occurrences of firing one additional heartbeat after a cancellation, you're better off keeping the code you have, as it is more efficient and more readable.