This seems so basic that I\'m sure I\'ve just overlooked a class or a method somewhere, but for the life of me, I can\'t find it.
I\'ve got a json string like so:
To add to Shaun McCarthy's answer there's a slightly cleaner way to achieve the exact same goal using BsonDocument.Parse
together with QueryDocument
:
var json = "{ SendId: 4, 'Events.Code' : { $all : [2], $nin : [3] } }";
collection.Find(new QueryDocument(BsonDocument.Parse(json)));
It's ugly, but you can do this by deserializing the string in to a BsonDocument
and then wrapping in a QueryDocument
BsonDocument query = MongoDB.Bson.Serialization.BsonSerializer.Deserialize<BsonDocument>("{ SendId: 4, 'Events.Code' : { $all : [2], $nin : [3] } }");
QueryDocument queryDoc = new QueryDocument(query);
var result = collection.FindAs<TypeOfResultExpected>(queryDoc); // or just use Find
If it's something you plan on doing frequently, you could always wrap it in a method, or create a JSQueryDocument
class like the following:
public class JSQueryDocument : QueryDocument
{
public JSQueryDocument(string query) : base(MongoDB.Bson.Serialization.BsonSerializer.Deserialize<BsonDocument>(query))
{
// Probably better to do this as a method rather than constructor as it
// could be hard to debug queries that are not formatted correctly
}
}
/// ...
var result = collection.Find(new JSQueryDocument("{ SendId: 4, 'Events.Code' : { $all : [2], $nin : [3] } }"));