Joining two consecutive lines using awk or sed

Question

How would I join two lines using awk or sed?

for e.g.:

I have data that looks like this:

abcd
joinabcd
efgh
joinefgh
ijkl
j         


        

Answer 1

They say imitation is the sincerest form of flattery.
Here's a Perl solution inspired by Dimitre's awk code:

perl -lne 'print "$_$p" if $. % 2 == 0; $p = $_' infile

$_ is the current line
$. is the line number

Answer 2

You can use printf with a ternary:

    awk '{printf (NR%2==0) ? $0 "\n" : $0}'

Answer 3

This is the answer to the question "How to make the count and the file appear on the same line" in the command:

find . -type f -exec fgrep -ci "MySQL" {} \; -print

Bryon Nicolson's answer produced the best result.

Answer 4

Some improvement to the "sed" script above that will take the following: 1008
-2734406.132904 2846
-2734414.838455 4636
-2734413.594009 6456
-2734417.316269 8276
-2734414.779617

  and make it :    

1008 -2734406.132904
2846 -2734414.838455
4636 -2734413.594009
6456 -2734417.316269
8276 -2734414.779617

  the "sed" is : "sed 'h;s/.*//;G;N;s/\n/ /g'"

Answer 5

awk 'BEGIN{i=1}{line[i++]=$0}END{j=1; while (j<i) {print line[j+1] line[j]; j+=2}}' yourfile

No need for sed.

Answer 6

awk '!(NR%2){print$0p}{p=$0}' infile