PHP foreach loop to populate dropdown list with values from an array of arrays

Question

I have an array of an arrays created using the following code. I\'m trying to get this to loop through and populate a dropdown list.

$names         


        

Answer 1

i think this is enough

foreach($names as $key =>$value)
{?>
<option value="<?=$value['name']?>"><?=$value['name']?></option>    
<?php }

Answer 2

This solution works for current PHP versions. Simple case of using a foreach:

<select name="per1" id="per1">
  <option selected="selected">Choose one</option>
  <?php
    foreach($names as $name) { ?>
      <option value="<?= $name['name'] ?>"><?= $name['name'] ?></option>
  <?php
    } ?>
</select> 

This solution works for older PHP versions. Simple case of using a foreach:

<select name="per1" id="per1">
  <option selected="selected">Choose one</option>
  <?php
    foreach($names as $name) { ?>
      <option value="<?php echo $name['name'] ?>"><?php echo $name['name'] ?></option>
  <?php
    } ?>
</select> 

Answer 3

Easiet way to use php array in dropdown html form or anywhere to show php foreach values in as dropdown values

<select name="city" required class="form-control"> 
   <option value="">Select City</option>
   <?php foreach($pkcities as $rows){ $city = $rows['city']; ?>
   <option  value="<?=$city;?>" ><?=$city;?></option>
   <?php } ?>
   </select>

Answer 4

Go for for each loop to avoid these much coding.

<?php 
foreach($names as $nameIndex=>$nameVal){ ?>
   <option value=$nameVal['name']?>"><?=$nameVal['name']?> </option>
<?php } ?>