How to get indexes of all occurrences of a pattern in a string

Question

string = \"Jack and Jill went up the hill to fetch a pail of water. Jack fell down and broke his crown. And Jill came tumbling after. \"
d = string.match(/(jack|jill         


        

Answer 1

You can use .scan and $` global variable, which means The string to the left of the last successful match, but it doesn't work inside usual .scan, so you need this hack (stolen from this answer):

string = "Jack and Jill went up the hill to fetch a pail of water. Jack fell down and broke his crown. And Jill came tumbling after. "  
string.to_enum(:scan, /(jack|jill)/i).map do |m,|
  p [$`.size, m]
end

output:

[0, "Jack"]
[9, "Jill"]
[57, "Jack"]
[97, "Jill"]

UPD:

Note the behaviour of lookbehind – you get the index of the really matched part, not the look one:

irb> "ab".to_enum(:scan, /ab/     ).map{ |m,| [$`.size, $~.begin(0), m] }
=> [[0, 0, "ab"]]
irb> "ab".to_enum(:scan, /(?<=a)b/).map{ |m,| [$`.size, $~.begin(0), m] }
=> [[1, 1, "b"]]

Answer 2

Here's a modification of Nakilon's answer if you want to put just the locations of "Jack" into an array

location_array = Array.new

string = "Jack and Jack went up the hill to fetch a pail of Jack..."  
string.to_enum(:scan,/(jack)/i).map do |m,|
    location_array.push [$`.size]
end