Upload file via sftp with python

Question

I wrote a simple code to upload a file to a sftp server in python. I am using python 2.7

import pysftp

srv = pysftp.Connection(host=\"www.destination.com\",         


        

Answer 1

I found the answer to my own question.

import pysftp

srv = pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log")

with srv.cd('public'): #chdir to public
    srv.put('C:\Users\XXX\Dropbox\test.txt') #upload file to nodejs/

# Closes the connection
srv.close()

Put the srv.put inside with srv.cd

Answer 2

import pysftp

with pysftp.Connection(host="www.destination.com", username="root",
password="password",log="./temp/pysftp.log") as sftp:

  srv.cwd('/root/public'): #Write the whole path
  srv.put('C:\Users\XXX\Dropbox\test.txt') #upload file to nodejs/

No srv.close() as connection closed automatically at the end of the with-block

I did a minor change with cd to cwd

Syntax -

# sftp.put('/my/local/filename')  # upload file to public/ on remote
# sftp.get('remote_file')         # get a remote file